Vector A having magnitude √2 units makes an angle 45∘ with horizontal and vector B having magnitude 2 units makes an angle 30∘ with horizontal as shown in the figure. What is →A−→B?
A
(1+√3)^i+2^j
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B
(1+√3)^i−2^j
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C
(1−√3)^i+2^j
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D
(1−√3)^i
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Solution
The correct option is D(1−√3)^i Taking components along the axes, the vector A can be written as →A=(√2cos45∘)^i+(√2sin45∘)^j =^i+^j
The vector B can be written as →B=(2cos30∘)^i+(2sin30∘)^j =√3^i+^j