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Question

# Vector →A is of length 2 cm and is inclined at 60∘ above the x -axis in the first quadrant. Vector →B is of length 2 cm and inclined at 60∘ below the x-axis in the fourth quadrant. The difference →A−→B is a vector of magnitude (cm)

A
2 cm along + y - axis
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B
23 cm along + y - axis
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C
1 cm along - x- axis
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D
2 cm along - x - axis
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Solution

## The correct option is B 2√3 cm along + y - axisLet us assume, →R=→A−→B =(Acos60^i+Asin60^j)−(Bcos60^i−Bsin60^j) ∵|→A|=|→B|=2 cm So, R=(Asin60+Bsin60)^j=2√3^j Hence 2√3 cm along + y -axis

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