Vector A-B and C have magnitude 5- 5-2 and 5 respectively- direction of A- B and C are towards East- North - East and North respectively- If - and - are unit vectors along East and North respectively- Find the magnitude and direction of the resultant-

A = 5 î, C = 5 ĵ B = 5√(2)cos 45 î + 5√(2)sin 45 ĵ =5 î + 5 ĵ A + B + C = 5 î + 5 î + 5 ĵ + 5ĵ = 10 î + 10ĵ |A+ B+C| = √((10)^2 +(10)^2) = 10 √(2) tanθ = 10/10 ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard XII

Physics

Vector Addition

Vector A,B an...

Question

Vector $\to A, \to B$ and $\to C$ have magnitude $5, 5 \sqrt{2}$ and 5 respectively, direction of $\to A, \to B$ and $\to C$ are towards East, North - East and North respectively. If $^i$ and $^j$ are unit vectors along East and North respectively. Find the magnitude and direction of the resultant.

10, 45^{\circ}

North of east

No worries! We‘ve got your back. Try BYJU‘S free classes today!

10 \sqrt{2}, 60^{\circ}

North of east

No worries! We‘ve got your back. Try BYJU‘S free classes today!

10 \sqrt{2}, 45^{\circ}

North of east

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

10 \sqrt{2}, 45^{\circ}

South of east

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C $10 \sqrt{2}, 45^{\circ}$ North of east
$\to A = 5^i, \to C = 5^j$
$\to B = 5 \sqrt{2} cos 45^i + 5 \sqrt{2} sin 45^j$
$= 5^i + 5^j$ $\to A + \to B + \to C = 5^i + 5^i + 5^j + 5^j = 10^i + 10^j$
$| \to A + \to B + \to C | = \sqrt{(10)^{2} + (10)^{2}} = 10 \sqrt{2}$ $tan θ = \frac{10}{10} = 1$
$θ = 45^{\circ}$ from East
Hence direction is $45^{\circ}$ from East or North East.

Suggest Corrections

Similar questions

Q. Vectors

\to A, \to B

and

\to C

have magnitudes

5, 5 \sqrt{2}

and 5 respectively and direction of

\to A, \to B

and

\to C

are towards East, North - East and North respectively. If

^i

and

^j

are unit vectors along East and North respectively. The magnitude and direction of the resultant respectively will be

Q. Vector

\to A, \to B

and

\to C

have magnitude

5, 5 \sqrt{2}

and 5 respectively, direction of

\to A, \to B

and

\to C

are towards East, North - East and North respectively. If

^i

and

^j

are unit vectors along East and North respectively. Find the magnitude and direction of the resultant.

Q. Vectors

\to A, \to B

and

\to C

have magnitudes

5, 5 \sqrt{2}

and 5 respectively and direction of

\to A, \to B

and

\to C

are towards East, North - East and North respectively. If

^i

and

^j

are unit vectors along East and North respectively. The magnitude and direction of the resultant respectively will be

The vectors b and c are in the direction of north-east and north-west respectively and $| b | = | c | = 4$ . The magnitude and direction of the vector d = c - b, are

Q. The vectors b and c are in the direction of north-east and north-west respectively and

| b | = | c | = 4

. The magnitude and direction of the vector d = c - b, are

Join BYJU'S Learning Program

Vector →A,→B and →C have magnitude 5,5√2 and 5 respectively, direction of →A,→B and →C are towards East, North - East and North respectively. If ^i and ^j are unit vectors along East and North respectively. Find the magnitude and direction of the resultant.

The correct option is C 10√2, 45∘ North of east→A=5^i,→C=5^j →B=5√2cos45^i+5√2sin45^j =5^i+5^j →A+→B+→C=5^i+5^i+5^j+5^j=10^i+10^j |→A+→B+→C|=√(10)2+(10)2=10√2 tanθ=1010=1 θ=45∘ from East Hence direction is 45∘ from East or North East.

Vector $\to A, \to B$ and $\to C$ have magnitude $5, 5 \sqrt{2}$ and 5 respectively, direction of $\to A, \to B$ and $\to C$ are towards East, North - East and North respectively. If $^i$ and $^j$ are unit vectors along East and North respectively. Find the magnitude and direction of the resultant.