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Question

Vectors a and b make an angle θ=2π3. If |a|=1,b=2 then {(a+3b)×(3ab)}2=

A
225
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B
250
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C
275
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D
300
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Solution

The correct option is C 300
{a×3aa×b+9b×a3b×b}2={a×b+9b×a}2
={10b×a}2
={10absin2π3}2
putting values of a and b we will get 300 as answer

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