Question

Velocity constant of a reaction at 290 K was found to $3.2\times {10}^{-3}se{c}^{-1}$. When the temperature is raised to 310 K, it will be about:

• A. $6.4\times {10}^{-3}$
• B. $3.2\times {10}^{-4}$
• C. $9.6\times {10}^{-3}$
• D. $1.28\times {10}^{-2}$

Answer 1

The correct option is D $1.28\times {10}^{-2}$

From the Arhenius eqn, we know that the rate of a reaction doubles for every 10 K rise in temperature.

$\frac{k_2}{k_1}=2^2\Rightarrow k_2=3.2\times {10}^{-3}\times 4=1.28\times {10}^{-2}se{c}^{-1}$