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1st Equation of Motion

Velocity in ...

Question

Velocity in $m / s$ of a particle moving along $x -$ axis varies with time as $v = (10 + 5 t - t^{2})$ . At time $t = 0, x = 0.$ Acceleration of particle at $t = 2 s$ is $x m / s^{2}$ , then value of $x$ is

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Solution

We have $a = \frac{d v}{d t} = 5 - 2 t$
At $t = 2 s, a = 5 - 2 \times 2 = 1 m / s^{2}$ .
Thus $x = 1.$

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