Question

Velocity of a particle at any instant is given by the equation $\overrightarrow{v}=(2t\hat{i}+3t^2\hat{j})m/s$, and radius of the curvature of the path is $2m$. Centripetal acceleration of the particle at $t=2s$ is:

• A. $80m/s^2$
• B. $\sqrt{160}m/s^2$
• C. $40m/s^2$
• D. $100m/s^2$

Answer 1

Answer: (A)

$80m/s^2$

Centripetal acceleration

$=\frac{v^2}{r}$

$=\frac{160}{2}=80m/s$