1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

# Velocity of a particle is in negative direction with constant acceleration in positive direction. Then, match the following columns. Column-I Column-II (a) Velocity-time graph (p) Slope→negative (b) Acceleration-time graph (q) Slope→positive (c) Displacement-time graph (r) Slope→zero (s) |Slope|→increasing (t) |Slope|→ decreasing (u) |Slope|→ constant

A
(Aq, u, Br, u, Cp, t)
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
(Aq, u, Br, u, Cp,u)
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
(Aq, u, Br, Cp, t)
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
(Aq, Br, u, Cp, t)
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

## The correct option is A (A→q, u, B→r, u, C→p, t)(A→q, u, B→r, u, C→p, t) Corresponding v−t, a−t and s−t graphs are as shown below

Suggest Corrections
0
Join BYJU'S Learning Program
Related Videos
Derivation of three equations of motion
PHYSICS
Watch in App
Join BYJU'S Learning Program