Question

Velocity of a particle moving in a circular in a curvilinear path varies with time as $\overrightarrow{V}=(2t\hat{i}+t^2\hat{j})m/s$. Then $t$ is in $sec$.At $t=1sec$

• A. Acceleration of particle is $8m/s^2$
• B. Tangential acceleration of particle is $\frac{6}{\sqrt{5}}m/s^2$
• C. Radial acceleration of particle is $\frac{1}{\sqrt{5}}m/s^2$
• D. Radius of curvature to the paths is $\frac{5\sqrt{5}}{2}m$

Answer 1

Answer: (B), (C), (D)

The correct options are
B Tangential acceleration of particle is $\frac{6}{\sqrt{5}}m/s^2$
C Radial acceleration of particle is $\frac{1}{\sqrt{5}}m/s^2$
D Radius of curvature to the paths is $\frac{5\sqrt{5}}{2}m$