The correct option is B decreases
From Bohr's model we know that
v=(e22πϵ0)1n
So velocity will decrease as electrons reach in higher orbits.
Similarly E = - (13.6n2) ev
The energy of an atom is the least (largest negative value) when its electron is revolving in an orbit closest to the nucleus i.e., the one for which n = 1. For n = 2, 3, ... the absolute value of the energy E is smaller, hence the energy is progressively larger in the outer orbits