Velocity of particle moving along a straight line at any time t is given by v-cos - 3 t - The distance travelled by the particle in the first two seconds is equal to

The correct option is A 3√( 3 ) 2π v=cos( π #160; 3 t ) #160; x= 3 π #160; sin( π #160; 3 t ) #160; At t=2sec, x= 3 π #160; ...

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Standard XII

Physics

Instantaneous Velocity

Velocity of p...

Question

Velocity of particle moving along a straight line at any time $t$ is given by $v = cos (\frac{π}{3} t)$ . The distance travelled by the particle in the first two seconds is equal to

\frac{\sqrt{3}}{2 π}

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\frac{3 \sqrt{3}}{2 π}

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\frac{3 \sqrt{3}}{π}

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zero

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Solution

The correct option is A $\frac{3 \sqrt{3}}{2 π}$
$v = cos (\frac{π}{3} t) x = \frac{3}{π} sin (\frac{π}{3} t)$
At t=2sec, $x = \frac{3}{π} sin (\frac{2 π}{3})$
$x = \frac{3 \sqrt{3}}{2 π} m$

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Velocity of particle moving along a straight line at any time t is given by v=cos(π3t). The distance travelled by the particle in the first two seconds is equal to

The correct option is A 3√32πv=cos(π3t)x=3πsin(π3t)At t=2sec,x=3πsin(2π3)x=3√32πm

Velocity of particle moving along a straight line at any time $t$ is given by $v = cos (\frac{π}{3} t)$ . The distance travelled by the particle in the first two seconds is equal to

The correct option is A $\frac{3 \sqrt{3}}{2 π}$
$v = cos (\frac{π}{3} t) x = \frac{3}{π} sin (\frac{π}{3} t)$
At t=2sec, $x = \frac{3}{π} sin (\frac{2 π}{3})$
$x = \frac{3 \sqrt{3}}{2 π} m$