Velocity of sound in the atmosphere of a planet is $500 m s^{- 1}$ . The minimum distance between the source of sound and the obstacle for an echo heard is

17 m

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50 m

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25 m

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20 m

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Solution

The correct option is C $25 m$
Let the distance between the source of sound and the obstacle be $x$ metres .
Thus the distance travelled by sound to reach back to the source $d = 2 x$
As the minimum time required to hear an echo is equal to $0.1 s e c$
Thus $d = v t$
$2 x = 500 (0.1) ⟹ x = 25 m$

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Similar questions

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Velocity of sound in the atmosphere of a planet is 500 ms−1. The minimum distance between the source of sound and the obstacle for an echo heard is

The correct option is C 25 mLet the distance between the source of sound and the obstacle be x metres .Thus the distance travelled by sound to reach back to the source d=2xAs the minimum time required to hear an echo is equal to 0.1secThus d=vt2x=500(0.1)⟹x=25m

Velocity of sound in the atmosphere of a planet is $500 m s^{- 1}$ . The minimum distance between the source of sound and the obstacle for an echo heard is

The correct option is C $25 m$
Let the distance between the source of sound and the obstacle be $x$ metres .
Thus the distance travelled by sound to reach back to the source $d = 2 x$
As the minimum time required to hear an echo is equal to $0.1 s e c$
Thus $d = v t$
$2 x = 500 (0.1) ⟹ x = 25 m$