Velocity of sound in the atmosphere of a planet is 600m $s^{- 1}$ . The minimum distance between the source of sound and the obstacle to hear echo should be

60 m

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25 m

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30 m

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17 m

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Solution

The correct option is C 30 m
Let the distance between the source of sound and the obstacle be $x$ metres .
Thus the distance travelled by sound to reach back to the source $d = 2 x$
As the minimum time required to hear an echo is equal to $0.1 s e c$
Thus $d = v t$
$2 x = 600 \times 0.1 ⟹ x = 30 m$

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Velocity of sound in the atmosphere of a planet is 600ms−1. The minimum distance between the source of sound and the obstacle to hear echo should be

The correct option is C 30 mLet the distance between the source of sound and the obstacle be x metres .Thus the distance travelled by sound to reach back to the source d=2xAs the minimum time required to hear an echo is equal to 0.1secThus d=vt2x=600×0.1⟹x=30m

Velocity of sound in the atmosphere of a planet is 600m $s^{- 1}$ . The minimum distance between the source of sound and the obstacle to hear echo should be