wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Velocity of the centre of mass of the rod after collision is

161149_a928da74517747449b1628d845191e6f.PNG

A
12 m/s
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
9 m/s
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
6 m/s
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
3 m/s
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is B 6 m/s
Net external force is zero Pi=Pf
Let V be the centre of mass of the rod after collision.
m1v1+m2v2+0=MV
2×10+1×10+0=(2+2+1)V
V=6 m/s

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
A No-Loss Collision
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon