Velocity ratio of a single movable pulley is

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Solution

The correct option is D 2
$V R = \frac{D i s t a n c e m o v e d b y e f f o r t}{D i s t a n c e m o v e d b y l o a d}$
$M A = \frac{2 E f f o r t}{E f f o r t} = 2$
When effort mved a distance x load moved a distance = x/2
So,
$V R = \frac{X}{X 12} = \frac{2 X}{X} = 2$

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Velocity ratio of a single movable pulley is

The correct option is D 2VR=DistancemovedbyeffortDistancemovedbyloadMA=2EffortEffort=2When effort mved a distance x load moved a distance = x/2So, VR=XX12=2XX=2

The correct option is D 2
$V R = \frac{D i s t a n c e m o v e d b y e f f o r t}{D i s t a n c e m o v e d b y l o a d}$
$M A = \frac{2 E f f o r t}{E f f o r t} = 2$
When effort mved a distance x load moved a distance = x/2
So,
$V R = \frac{X}{X 12} = \frac{2 X}{X} = 2$