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Question

# Velocity-time graph of a particle moving in a straight line is shown in figure. At time t=0, s=20 m. Plot a-t and s-t graphs of the particle.

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Solution

## for acceleration vs time graph:from t=0 to t=4;a=0ms−2from t=4 to t=6change in velocity=20m/s;a=10ms−2from t=6 to t=8 change in velocity=−20m/s;a=−10ms−2from t=8 to t=12 change in velocity=40m/s;a=10ms−2from t=12 to t=14 change in velocity=20m/s;a=−10ms−2for displacement vs time graph:change in displacement is an area under the v vs t graphso from t=0 to t=4as velocity is constant so the graph of s vs t will be linearchange in diplacement=-80mfrom t=4 to t=6as velocity is linearly changing the s vs t will vary parabolicallychange in diplacement=-20mfrom t=6 to t=8as velocity is linearly changing the s vs t will vary parabolicallychange in displacement=-20mfrom t=8 to 12as velocity is linearly changing the s vs t will vary parabolicallychange in displacement =0mfrom t=12 to t=14as velocity is linearly changing the s vs t will vary parabolicallychange in diplacement=20m

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