Velocity-time graphs of two cars which start from rest at the same time, are shown in the figure. Graph shows that

initial velocity of A is greater than the initial velocity of B

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acceleration in A is increasing at lesser rate than in B

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acceleration in A is greater than in B

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acceleration in B is greater than in A

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Solution

The correct option is C acceleration in A is greater than in B
Slope is given by tan θ,

At a certain instant $t$ , slope of A is greater than $B (θ_{A} > θ_{B})$ , so acceleration in A is greater than B

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Velocity-time graphs of two cars which start from rest at the same time, are shown in the figure. Graph shows that

The correct option is C acceleration in A is greater than in BSlope is given by tan θ, At a certain instant t, slope of A is greater than B (θA>θB), so acceleration in A is greater than B

The correct option is C acceleration in A is greater than in B
Slope is given by tan θ,

At a certain instant $t$ , slope of A is greater than $B (θ_{A} > θ_{B})$ , so acceleration in A is greater than B