1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

# Velocity (V) versus displacement (S) graph of a particle moving in a straight line is as shown in the figure. Given Vo=4 m/s and So=20 m. Corresponding acceleration (a) versus displacement (S) graph of the particle would be

A
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

## The correct option is A From S=0 to S=So velocity is given by, V=VoSoS⇒dVdt=VoSo(dSdt) ⇒Acceleration, a=VoSo(VoSoS) ⇒a=V2oS2o.S ⇒a∝S From S=So to S=2So, velocity is given by V=−VoSoS+2Vo dVdt=−VoSo(dSdt) Accleration, a=−VoSo(−VoSoS+2Vo)=V2oS2o.S−2V2oSo At S=So, a=−V2oSo and at S=2So, a=0 Hence, graph (a) is correct.

Suggest Corrections
0
Join BYJU'S Learning Program
Related Videos
Instantaneous acceleration
PHYSICS
Watch in App
Explore more
Join BYJU'S Learning Program