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Byju's Answer
Standard XII
Business Studies
Motivation
Velocity vect...
Question
Velocity vector of a flow field is given as
→
V
=
2
x
y
^
i
−
x
2
z
^
j
. The vorticity vector at (1, 1, 1) is
A
4
^
i
−
^
j
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B
4
^
i
−
^
k
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C
^
i
−
4
^
j
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D
^
i
−
4
^
k
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Solution
The correct option is
D
^
i
−
4
^
k
V
o
r
t
i
c
i
t
y
v
e
c
t
o
r
=
∣
∣ ∣ ∣ ∣
∣
i
j
k
∂
∂
x
∂
∂
y
∂
∂
z
2
x
y
−
x
2
z
0
∣
∣ ∣ ∣ ∣
∣
=
^
i
[
0
−
∂
∂
z
(
−
x
2
z
)
]
−
^
j
[
0
−
∂
∂
z
(
2
x
y
)
]
+
^
k
[
∂
∂
x
(
−
x
2
z
)
−
∂
∂
y
(
2
x
y
)
]
=
^
i
(
x
2
)
+
0
+
^
k
(
−
2
x
z
−
2
x
)
∴
At ( 1, 1, 1)
Vorticity vector =
^
i
−
4
^
k
Suggest Corrections
2
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