Venay bought a prizza and cut it into three pieces. When he weighed the first piece he found that it was $7 g$ lighter than the second piece and $4 g$ heavier than the third piece. If the whole pizza weighed $300 g$ . How much did each of the three pieces weigh?

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Solution

Let weigt of first piece $= a g$
weight of second piece $= (a + 7) g$
weight of third piece= $(a - 4) g$
Total weight of pizza $= 300 g$
$a + a + 7 + a .4 = 300$
$3 a = 297$
$a = 99 g$
$∴$ weight of first, second and third pieces are $99 g, 106 g, 95 g$ respectively.

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Venay bought a prizza and cut it into three pieces. When he weighed the first piece he found that it was 7g lighter than the second piece and 4g heavier than the third piece. If the whole pizza weighed 300g. How much did each of the three pieces weigh?

Let weigt of first piece =agweight of second piece =(a+7)gweight of third piece=(a−4)gTotal weight of pizza =300ga+a+7+a.4=3003a=297a=99g∴ weight of first, second and third pieces are 99g,106g,95g respectively.

Venay bought a prizza and cut it into three pieces. When he weighed the first piece he found that it was $7 g$ lighter than the second piece and $4 g$ heavier than the third piece. If the whole pizza weighed $300 g$ . How much did each of the three pieces weigh?

Let weigt of first piece $= a g$
weight of second piece $= (a + 7) g$
weight of third piece= $(a - 4) g$
Total weight of pizza $= 300 g$
$a + a + 7 + a .4 = 300$
$3 a = 297$
$a = 99 g$
$∴$ weight of first, second and third pieces are $99 g, 106 g, 95 g$ respectively.