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Question

verify: (1cos2y+sin2y)2+4sin2ycos2y=4sin2y

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Solution

LHS=((1cos2y)+sin2y)2+4sin2ycos2y
=(sin2y+sin2y)2+4sin2ycos2y
=(2sin2y)2+4sin2ycos2y
=4sin4y+4sin2ycos2y
=4sin2y(sin2y+cos2y)
=4sin2y1
=4sin2y
=RHS

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