Given matrix is,
A=[ 2 3 −4 −6 ]
The determinant of the given matrix is,
| A |=2×( −6 )−( −4 )×3 =−12+12 =0
Calculate | A |I,
| A |I=0×[ 1 0 0 1 ] =[ 0 0 0 0 ]
Cofactor of a 11 is,
A 11 = ( −1 ) 1+1 ( −6 ) =−6
Cofactor of a 12 is,
A 12 = ( −1 ) 1+2 ( −4 ) =4
Cofactor of a 21 is,
A 21 = ( −1 ) 2+1 ( 3 ) =−3
Cofactor of a 22 is,
A 22 = ( −1 ) 2+2 ( 2 ) =2
So the adjoint of the given matrix is,
adjA=[ A 11 A 21 A 12 A 22 ] =[ −6 −3 4 2 ]
Calculate A( adjA ),
A( adjA )=[ 2 3 −4 −6 ][ −6 −3 4 2 ] =[ −12+12 −6+6 24−24 12−12 ] =[ 0 0 0 0 ] =| A |I
Calculate ( adjA )A,
adjA( A )=[ −6 −3 4 2 ][ 2 3 −4 −6 ] =[ −12+12 −18+18 8−8 12−12 ] =[ 0 0 0 0 ] =| A |I
Hence, it is verified that A( adjA )=adjA( A )=| A |I.