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Question

Verify A ( adj A ) = ( adj A ) A = I .

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Solution

Given matrix is,

A=[ 2 3 4 6 ]

The determinant of the given matrix is,

| A |=2×( 6 )( 4 )×3 =12+12 =0

Calculate | A |I,

| A |I=0×[ 1 0 0 1 ] =[ 0 0 0 0 ]

Cofactor of a 11 is,

A 11 = ( 1 ) 1+1 ( 6 ) =6

Cofactor of a 12 is,

A 12 = ( 1 ) 1+2 ( 4 ) =4

Cofactor of a 21 is,

A 21 = ( 1 ) 2+1 ( 3 ) =3

Cofactor of a 22 is,

A 22 = ( 1 ) 2+2 ( 2 ) =2

So the adjoint of the given matrix is,

adjA=[ A 11 A 21 A 12 A 22 ] =[ 6 3 4 2 ]

Calculate A( adjA ),

A( adjA )=[ 2 3 4 6 ][ 6 3 4 2 ] =[ 12+12 6+6 2424 1212 ] =[ 0 0 0 0 ] =| A |I

Calculate ( adjA )A,

adjA( A )=[ 6 3 4 2 ][ 2 3 4 6 ] =[ 12+12 18+18 88 1212 ] =[ 0 0 0 0 ] =| A |I

Hence, it is verified that A( adjA )=adjA( A )=| A |I.


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