Verify by calculating that 240 g of calcium and 240 g magnesium elements have mole ratio of 3 : 5.

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Solution

We know that
Part 1:
Molar mass of Calcium ( $Ca$ )=40 g/ mol
Number of moles of Calcium= $\frac{240 g}{40 g / m o l} = 6 m o l$
Part 2:
Molar mass of Magnesium ( $Mg$ )=24 g / mol
Number of moles of Magnesium( $Mg$ )= $\frac{240 g}{24 g / m o l} = 10 m o l$
So the mole ratio of calcium to Magnesium =6 mol:10 mol= 3:5

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Verify by calculating that $240 g$ of calcium and $240 g$ magnesium elements have a mole ratio of $3 : 5$ .

Question 24
Verify by calculating that

(a) 5 moles of $C O_{2}$ and 5 moles of $H_{2} O$ do not have the same mass.

(b) 240 g calcium and 240 g magnesium elements have a mole ratio of 3:5.

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2. Verify by calculating that

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240 g of calcium and 240 g of magnesium elements have a mole ratio of 3:5.

Q. 240 g of calcium and 240 g magnesium elements have a mole ratio of a:b. What is a:b ?

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Verify by calculating that 240 g of calcium and 240 g magnesium elements have mole ratio of 3 : 5.

We know thatPart 1:Molar mass of Calcium (Ca)=40 g/ molNumber of moles of Calcium=240g40g/mol=6molPart 2:Molar mass of Magnesium (Mg)=24 g / molNumber of moles of Magnesium( Mg)=240g24g/mol=10molSo the mole ratio of calcium to Magnesium =6 mol:10 mol= 3:5