We need to verify Rolle's theorem for
f(x)=e−xsinx on
[0,π]
e−x and sinx are continuous for all x,therefore the product e−xsinx is continuous in 0≤x≤π
f′(x)=−e−xsinx+e−xcosx=e−x(cosx−sinx) exists in 0<x<π
⇒f(x) is differentiable in (0,π)
f(0)=e0sin0=0,f(π)=eπsinπ=0
Therefore f satisfies the hypothesis of Rolle's theorem.
Thus there exists c∈(0,π) satisfying f′(c)=0⇒e−c(cosc−sinc)=0
⇒e−c=0orcosc−sinc=0
⇒e−c=0orcotc=1
But ex can never be zero, so e−c≠0
⇒c=π4
Hence c=π4 is the required point.