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Question

Verify Rolle's theorem for the function f(x)=loge[x2+abx(a+b)]+p, for [a,b] where 0<a<b.

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Solution

f(x)=loge[x2+abx(a+b)]+p, for [a,b] where 0<a<b
Now, f(x)=logex functions are continuous as well as differentiable for x>0
Now, f(x)=loge[x2+abx(a+b)] to be verifying Relle's theorem, must we have x2+abx(a+b)>0
As 0<a<b
ab>0
& x2>0
Therefore (x2+ab)>0
Now, x(a+b)>0, as x lies in [a,b] and (a+b)>0
Thus x2+abx(a+b)>0 and f(x) follows Relle's theorem.

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