f(x)=x3−6x2+11x−6
f(x) is cont on [1,3]
And differentiable on (1,3)
Being a polyonomial,
Now f(a)=f(4)=1−6+11−6=0
f(b)=f(3)=27−54+33−6=0
f(a)=f(b)
Hence rolies theorem is verified