Verify that 1/2 , 1 and -2 are the zeroes of the cubic polynomial 2x³ + x² -5x + 2

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Solution

Try putting every value (1/2,1,-2) instead of 'x' in the equation , if every time the equation becomes zero , then you have verified that these are the zeroes !”

on putting 1 , u get :
2+1-5+2 = 0

on putting 1/2 ,
(2+8-10)/4 = 0

on putting -2 ,
-16+19+4+2 = 0

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Similar questions

\frac{1}{2}

2 x^{3} + x^{2} - 5 x + 2

2 x^{3} + x^{2} - 5 x + 2, (\frac{1}{2}, 1 . - 2)

f (x) = 2 x^{3} + x^{2} - 5 x + 2; \frac{1}{2}, 1, - 2

2 x^{3} + x^{2} - 5 x + 2; \frac{1}{2}, 1, - 2

x^{3} - 4 x^{2} + 5 x - 2; 2, 1, 1

f (x) = 2 x^{3} + x^{2} - 5 x + 2; \frac{1}{2}, 1, - 2

g (x) = x^{3} - 4 x^{2} + 5 x - 2; 2, 1, 1

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