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Question

Verify that 3,2,1 are the zeroes of the cubic polynomial p(x)=(x32x25x+6) and verify the relationship between its zeroes and coefficients.

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Solution

Let f(x)=x32x25x+6
3,2 and 1 are the zeroes of the polynomial ( given )
Therefore,
f(3)=(3)32(3)25(2)+6
=271815+6
=0
f(2)=(2)32(2)25(2)+6
88+10+6
=0
f(1)=(1)32(1)25(1)+6
=125+6
=0
Verify relations :
General form of cubic equation :ax3+bx2+cx+d
now ,
Consider α=3,β=2 and y=1
α+β+y=32+1=2=b/a
αβ+βy+αy=3(2)+(2)(1)+1(3)=5=c/a
and αβy=3(2)(1)=6=d/a

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