(i) p(x)=x−4⇒p(4)=4−4=0
Hence, 4 is the zero of the given polynomial.
(ii) q(x)=x+3⇒q(−3)=−3+3⇒q(−3)=0
Hence, 3 is the zero of the given polynomial.
(iii) f(x)=2−5x⇒f(25)=2−5×25=2−2=0
Hence, 25 is the zero of the given polynomial.
Verify that (i) 4 is a zero of the polynomial, p(x) = x - 4. (ii) -3 is a zero of the polynomial, q (x) = x + 3. (iii) 25 is a zero of the polynomial, f(x)=2−5x (iv) −12 is a zero of the polynomial, g(y) = 2y + 1.