Verify that
(i) 4 is a zero of the polynomial, p(x) = x - 4.
(ii) -3 is a zero of the polynomial, q (x) = x + 3.
(iii) $\frac{2}{5}$ is a zero of the polynomial, $f (x) = 2 - 5 x$

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Solution

(i) $p (x) = x - 4 \Rightarrow p (4) = 4 - 4 = 0$

Hence, 4 is the zero of the given polynomial.

(ii) $q (x) = x + 3 \Rightarrow q (- 3) = - 3 + 3 \Rightarrow q (- 3) = 0$

Hence, 3 is the zero of the given polynomial.

(iii) $f (x) = 2 - 5 x \Rightarrow f (\frac{2}{5}) = 2 - 5 \times \frac{2}{5} = 2 - 2 = 0$

Hence, $\frac{2}{5}$ is the zero of the given polynomial.

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Similar questions

Q. Verify that
(i) 4 is a zero of the polynomial, p(x) = x - 4.
(ii) -3 is a zero of the polynomial, q (x) = x + 3.
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\frac{2}{5}

is a zero of the polynomial,

f (x) = 2 - 5 x

Verify that
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(ii) -3 is a zero of the polynomial, q (x) = x + 3.
(iii) $\frac{2}{5}$ is a zero of the polynomial, $f (x) = 2 - 5 x$
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Verify that (i) 4 is a zero of the polynomial, p(x) = x - 4. (ii) -3 is a zero of the polynomial, q (x) = x + 3. (iii) 25 is a zero of the polynomial, f(x)=2−5x

(i) p(x)=x−4⇒p(4)=4−4=0 Hence, 4 is the zero of the given polynomial. (ii) q(x)=x+3⇒q(−3)=−3+3⇒q(−3)=0 Hence, 3 is the zero of the given polynomial. (iii) f(x)=2−5x⇒f(25)=2−5×25=2−2=0 Hence, 25 is the zero of the given polynomial.

Verify that
(i) 4 is a zero of the polynomial, p(x) = x - 4.
(ii) -3 is a zero of the polynomial, q (x) = x + 3.
(iii) $\frac{2}{5}$ is a zero of the polynomial, $f (x) = 2 - 5 x$