Verify that
(i) 4 is a zero of the polynomial, p(x) = x - 4.
(ii) -3 is a zero of the polynomial, q (x) = x + 3.

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Solution

(i) $p (x) = x - 4 \Rightarrow p (4) = 4 - 4 = 0$

Hence, 4 is the zero of the given polynomial.

(ii) $q (x) = x + 3 \Rightarrow q (- 3) = - 3 + 3 \Rightarrow q (- 3) = 0$

Hence, 3 is the zero of the given polynomial.

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Verify that (i) 4 is a zero of the polynomial, p(x) = x - 4. (ii) -3 is a zero of the polynomial, q (x) = x + 3.

(i) p(x)=x−4⇒p(4)=4−4=0 Hence, 4 is the zero of the given polynomial. (ii) q(x)=x+3⇒q(−3)=−3+3⇒q(−3)=0 Hence, 3 is the zero of the given polynomial.

Verify that
(i) 4 is a zero of the polynomial, p(x) = x - 4.
(ii) -3 is a zero of the polynomial, q (x) = x + 3.

(i) $p (x) = x - 4 \Rightarrow p (4) = 4 - 4 = 0$

Hence, 4 is the zero of the given polynomial.

(ii) $q (x) = x + 3 \Rightarrow q (- 3) = - 3 + 3 \Rightarrow q (- 3) = 0$

Hence, 3 is the zero of the given polynomial.