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Question

Verify that the given functions (explicit or implicit) is a solution of the corresponding differential equation:
y=x2+2x+C:y2x2=0.

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Solution

Let,
y=x2+2x+C
Differentiating both sides w.r.t. x, then we get
y=(x2+2x+c)
y=2x+2+0
y=2x+2
Taking LHS
y2x2=2x+22x2
y2x2=0
Thus LHS=RHS
Hence verified.

Final answer:
Hence, the function y=x2+2x+C is a solution of the differential equation y2x2=0.

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