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Question

Verify that x3+y3+z23xy2=12(x+y+z)[(zxy)2+(yz)2+(zx)2]

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Solution

x3+y3+z23xyz
=(x+y+z)(x2+y2+z2xyyzzx)
=12(x+y+z)(2x2+2y2+2z22xy2yz2zx)
=12(x+y+z)(x2+y22xy+y2+z22yz+x2+z22zx)
=12(x+y+z)[(xy)2+(yz)2+(zx)2]

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