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Question

Verify that xy = a ex + b e−x + x2 is a solution of the differential equation xd2ydx2+2dydx-xy+x2-2=0.

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Solution

We have,xy=aex+be-x+x2Differentiating with respect to x on both sides, we getxdydx+y=aex-be-x+2xAgain differentiating with respect to x on both sides, we getxd2ydx2+dydx+dydx=aex+be-x+2xd2ydx2+2dydx=xy-x2+2 xy=aex+be-x+x2xd2ydx2+2dydx-xy+x2-2=0
Thus, xy = a ex + b e−x + x2 is the solution of the given differential equation.

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