CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Verify that xy = a ex + b e−x + x2 is a solution of the differential equation xd2ydx2+2dydx-xy+x2-2=0.

Open in App
Solution

We have,xy=aex+be-x+x2Differentiating with respect to x on both sides, we getxdydx+y=aex-be-x+2xAgain differentiating with respect to x on both sides, we getxd2ydx2+dydx+dydx=aex+be-x+2xd2ydx2+2dydx=xy-x2+2 xy=aex+be-x+x2xd2ydx2+2dydx-xy+x2-2=0
Thus, xy = a ex + b e−x + x2 is the solution of the given differential equation.

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Differential Equations - Classification
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon