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Question

Verify the division algorithm i.e. Dividend = Divisor × Quotient + Remainder, in each of the following. Also, write the quotient and remainder.
Dividend Divisor
(i) 14x2 + 13x − 15 7x − 4
(ii) 15z3 − 20z2 + 13z − 12 3z − 6
(iii) 6y5 − 28y3 + 3y2 + 30y − 9 2y2 − 6
(iv) 34x − 22x3 − 12x4 − 10x2 − 75 3x + 7
(v) 15y4 − 16y3 + 9y2 − 103y + 6 3y − 2
(vi) 4y3 + 8y + 8y2 + 7 2y2 − y + 1
(vii) 6y5 + 4y4 + 4y3 + 7y2 + 27y + 6 2y3 + 1

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Solution

(i)

Quotient = 2x + 3
Remainder = -3
Divisor = 7x - 4
Divisor × Quotient + Remainder = (7x - 4) (2x + 3) - ​3
= 14x2 + 21x - 8x - 12 - ​3
= 14x2 + 13x - 15
= Dividend
Thus,
Divisor × Quotient + Remainder = Dividend
Hence verified.

(ii)

Quotient = 5z2+103z+11Remainder = 54Divisor = 3z-6Divisor × Quotient +Remainder = (3z-6) 5z2+103z+11+54 = 15z3+10z2+33z-30z2-20z-66+54 = 15z3-20z2+13z-12 = DividendThus,Divisor × Quotient + Remainder = Dividend
Hence verified.

(iii)


Quotient = 3y3-5y+32
Remainder = 0
Divisor = 2y2 - 6
Divisor × Quotient + Remainder =
(2y2-6) 3y3-5y+32+0=6y5-10y3+3y2-18y3+30y-9=6y5-28 y3+3y2+30y-9
= Dividend

Thus, Divisor × Quotient + Remainder = Dividend
Hence verified.

(iv)

Quotient = - 4x3 + 2x2 - 8x + 30
Remainder = - 285
Divisor = 3x + 7
Divisor × Quotient + Remainder = (3x + 7) (- 4x3 + 2x2 - 8x + 30) - 285
= - 12x4 + 6x3 - 24x2 + 90x - 28x3 + 14x2 - 56x + 210 - ​285
= - 12x 4 - 22x3 - 10x2 + 34x - 75
= Dividend
Thus,
Divisor × Quotient + Remainder = Dividend
Hence verified.

(v)


Quotient = 5y3-2y2+53y
Remainder = 6
Divisor = 3y - 2
Divisor × Quotient + Remainder = (3y - 2) (5y3 - 2y2 + 53y) + 6
= 15y4-6y3+5y2-10y3+4y2-103y+6
= 15y4-16y3+9y2-103y+6
= Dividend
Thus,
Divisor × Quotient + Remainder = Dividend
Hence verified.

(vi)

Quotient = 2y + 5
Remainder = 11y + 2
Divisor = 2y2 - y + 1
Divisor × Quotient + Remainder = (2y2 - y + 1) (2y + 5) + 11y + 2
= 4y3 +10y2 - 2y2 - 5y + 2y + 5 + 11y + 2
= 4y3 + 8y2 + 8y + 7
= Dividend
Thus,
Divisor × Quotient + Remainder = Dividend
Hence verified.

(vii)




Quotient = 3y2 + 2y + 2
Remainder = 4y2 + 25y + 4
Divisor = 2y3 + 1
Divisor × Quotient + Remainder = (2y3 + 1) (3y2 + 2y + 2) + 4y2 + 25y + 4
= 6y5 + 4y4 + 4y3 + 3y2 + 2y + 2 + 4y2 + 25y + 4
= 6y5 + 4y4 + 4y3 + 7y2 + 27y + 6
= Dividend
Thus,
Divisor × Quotient + Remainder = Dividend
Hence verified.

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