Question

Verify the following:
$(\frac{-9}{5}\times \frac{-10}{3})\times \frac{21}{-4}=\frac{-9}{5}\times (\frac{-10}{3}\times \frac{21}{-4})$

Answer 1

$L.H.S=\left(\frac{-9}{5}\times \frac{-10}{3}\right)\times \frac{21}{-4}$d

$={\left(6\right)}^3\times \frac{21}{-4}$

$=\frac{-63}{2}$

$R.H.S=\frac{-9}{5}\times \left(\frac{-10}{3}\times \frac{21}{-4}\right)$

$=\frac{-9}{5}\times \left(\frac{35}{2}\right)$

$=\frac{-63}{2}$

$L.H.S=R.H.S$