Verify the identity : sinx+π2=cosx
Verifying the trigonometric identity Given trigonometric expression is sinx+π2=cosx.Taking L.H.S⇒sinx+π2=sinx.cosπ2+cosx.sinπ2∵sin(a+b)=sinacosb+cosasinb=sinx.0+cosx.1[∵cos(π2)=0andsin(π2)=1]
=cosx
=L.H.S
Hence proved.