Question

Verify the relation between zeroes and coefficients of the Quadratic polynomial $x^2-4$.

Answer 1

$x^2-4=0$

Here $a=1,b=0,c=-4$

$x^2=4$

$\Rightarrow x=\pm 2$

Therefore, the roots of the given equation are $\pm 2$.

As we know that,

Sum of roots $=\frac{-b}{a}$

$-2+2=\frac{0}{1}$

$0=0$

L.H.S $=$ R.H.S.

Product of roots $=\frac{c}{a}$

$-2\times 2=\frac{-4}{1}$

$-4=-4$

L.H.S. $=$ R.H.S.