Verify whether $2$ and $1$ are zeroes of the polynomial $x^{2} - 3 x + 2$ .

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Solution

Let $p (x) = x^{2} - 3 x + 2$
Replace $x$ by $2$
$p (2) = (2)^{2} - 3 (2) + 2$
$= 4 - 6 + 2 = 0$
Also replace $x$ by $1$
$p (1) = (1)^{2} - 3 (1) + 2$
$= 1 - 3 + 2$
$= 0$
Hence, both $2$ and $1$ are zeroes of the polynomial $x^{2} - 3 x + 2$ .
It is a quadratic polynomial. Hence, a quadratic polynomial has two zeroes.

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Q. Verify whether the following are zeroes of the polynomial, indicated against them.

p (x) = 3 x + 2; x = \frac{- 2}{3}

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(iii) 0 and 3 are the zeros of the polynomial, $r (x) = x^{2} - 3 x$ .

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Q. Verify whether the following are zeroes of the polynomial, indicated against them.
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- \frac{1}{3}

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Verify whether 2 and 1 are zeroes of the polynomial x2−3x+2.

Let p(x)=x2−3x+2Replace x by 2p(2)=(2)2−3(2)+2=4−6+2=0Also replace x by 1p(1)=(1)2−3(1)+2=1−3+2=0Hence, both 2 and 1 are zeroes of the polynomial x2−3x+2.It is a quadratic polynomial. Hence, a quadratic polynomial has two zeroes.

Verify whether $2$ and $1$ are zeroes of the polynomial $x^{2} - 3 x + 2$ .