Verify whether -2- 1-2 are zeroes of 2 x 3-3 x 2-11 x -6- -2 MARKS-

Concept : 1 Mark Verification : 1 Mark For any a to be a zero of a polynomial f(x), nbsp; f(a) = 0 ∴ f( 2 )= 16 12 +22 + 6 = 0 f(1/2) nbsp;= 1/4 nbsp ...

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Standard VIII

Mathematics

Reducing Equations to Simpler Form

Verify whethe...

Question

Verify whether -2, $\frac{1}{2}$ are zeroes of $2 x^{3} - 3 x^{2} - 11 x + 6$ . [2 MARKS]

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Solution

Concept : 1 Mark
Verification : 1 Mark

For any $a$ to be a zero of a polynomial $f (x)$ ,

$f (a) = 0$

$∴ f (- 2) = - 16 - 12 + 22 + 6 = 0$

$f (\frac{1}{2}) = \frac{1}{4} - \frac{3}{4} - \frac{11}{2} + 6 = 0$

$∴ - 2 a n d \frac{1}{2}$ are zeroes of the given equation.

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Verify whether -2, 12 are zeroes of 2x3−3x2−11x+6. [2 MARKS]

Concept : 1 Mark Verification : 1 Mark For any a to be a zero of a polynomial f(x), f(a)=0 ∴f(−2)=−16−12+22+6=0 f(12)=14−34−112+6=0 ∴−2 and 12 are zeroes of the given equation.

Verify whether -2, $\frac{1}{2}$ are zeroes of $2 x^{3} - 3 x^{2} - 11 x + 6$ . [2 MARKS]

Concept : 1 Mark
Verification : 1 Mark

For any $a$ to be a zero of a polynomial $f (x)$ ,

$f (a) = 0$

$∴ f (- 2) = - 16 - 12 + 22 + 6 = 0$

$f (\frac{1}{2}) = \frac{1}{4} - \frac{3}{4} - \frac{11}{2} + 6 = 0$

$∴ - 2 a n d \frac{1}{2}$ are zeroes of the given equation.