Points : 1 Mark each
The equation given is 4x + 3y = 16
1. Putting (1, 4) in the equation
(4×1)+(3×4)=16
The equation holds. Hence, (1, 4) is a solution.
2. Putting (2, 3) in the equation
(4×2)+(3×3)=17≠16
The equation does not hold. Hence, (2, 3) is not a solution.
3. Putting (3, 1) in the equation
(4×3)+(3×1)=15≠16
The equation does not hold. Hence, (3, 1) is not a solution.
4. Putting (4, 0) in the equation
(4×4)+(3×0)=16
The equation holds. Hence, (4, 0) is a solution.