Verify whether the following are true or false.
(i) -3 is a zero of x - 3
(ii) −13 is a zero of 3x + 1
(iii) −45 is a zero of 4 - 5y
(iv) 0 and 2 are the zeroes of t2–t
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Solution
(i) False. Zero of x – 3 is 3. [∵x−3=0⇒x=3]
(ii) True. Zero of 3x+1 is−13. [∵3x+1=0⇒x=−13]
(iii) False. Zero of 4 - 5y is45. [∵4−5y=0⇒y=45]
(iv)True. t2–2t=t(t–2)
Hence, zeroes of t2–2t are 0 and 2.