Verify whether the following are zeroes of the polynomial, indicated against them.
$p (x) = x^{2} - 1, x = 1, - 1$

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Solution

$p (x) = x^{2} - 1$
$x^{2} - 1 = 0$
$x^{2} = 1$
So $x = \pm 1$
$∴ x = 1, - 1$ are the roots of $p (x)$ .

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Verify whether the following are zeroes of the polynomial, indicated against them.p(x)=x2−1,x=1,−1

p(x)=x2−1x2−1=0x2=1So x=±1∴x=1,−1 are the roots of p(x).

Verify whether the following are zeroes of the polynomial, indicated against them.
$p (x) = x^{2} - 1, x = 1, - 1$

$p (x) = x^{2} - 1$
$x^{2} - 1 = 0$
$x^{2} = 1$
So $x = \pm 1$
$∴ x = 1, - 1$ are the roots of $p (x)$ .