Verify whether the following are zeros of the polynomial, indicated against them.

1.. P(x) = 3x + 1, x=1/3

2.. p(y) = (x+1)(x+2), x= -2

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Solution

You have to just verify that the 'x' value given is the zero of the given polynomial.
For that you have to substitute the value of 'x' in given polynomial and see whether that comes out to be zero.

1. P(x) = 3x + 1, x=1/3
If you substitute x=1/3, the P(x)=2 which is not equal to 0.
So, x=1/3 is not a zero of P(x)

2. P(x) = (x+1)(x+2), x= -2
If you substitute x=-2,
P(x) = (x+1)(x+2) = (-2+1)(-2+2) = -1 x 0 = 0
So, here P(x) turns out to be zero.
So, x=-2 is not a zero of P(x)

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Similar questions

Verify whether the following is zeroes of the polynomial, indicated against them.
$p (x) = 3 x + 1, x = - \frac{1}{3}$

Verify whether the following are zeroes of the polynomial, indicated against them.
(i) p(x)=3x+1,x= $\frac{- 1}{3}$

(ii) p(x)=5x− $π$ ,x= $\frac{4}{5}$

(iii) p(x)= $x^{2}$ -1,x=1,−1

(iv) p(x)=(x+1)(x−2),x=−1,2

(v) p(x)= $x^{2}$ ,x=0

p (x) = 3 x^{2} - 1, x = - \frac{1}{\sqrt{3}}, \frac{2}{\sqrt{3}}

p (x) = 3 x^{2} - 1, x = - \frac{1}{\sqrt{3}}, \frac{1}{\sqrt{3}}

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