Verify whether the following is zeros of the polynomial, indicated against them.
$p (x) = x^{2} - 1, x = 1, - 1$

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Solution

$p (x) = x^{2} - 1$
$x = \pm 1$
$p (1) = 1^{2} - 1 = 0$
$p (- 1) = (- 1)^{2} - 1 = 0$
Since $p (x) = 0$ for $x = \pm 1$
So, $x = \pm 1$ are zero of $p (x)$

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Verify whether the following is zeros of the polynomial, indicated against them.p(x)=x2−1, x=1,−1

p(x)=x2−1x=±1p(1)=12−1=0p(−1)=(−1)2−1=0Since p(x)=0 for x=±1So, x=±1 are zero of p(x)

Verify whether the following is zeros of the polynomial, indicated against them.
$p (x) = x^{2} - 1, x = 1, - 1$

$p (x) = x^{2} - 1$
$x = \pm 1$
$p (1) = 1^{2} - 1 = 0$
$p (- 1) = (- 1)^{2} - 1 = 0$
Since $p (x) = 0$ for $x = \pm 1$
So, $x = \pm 1$ are zero of $p (x)$