Verify whether the indicated numbers are zero of the polynomial given
$p (x) = x^{2} - 4$ at $x = 2, x = - 2$

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Solution

In the given polynomial $p (x) = x^{2} - 4$ , substitute $x = - 2$ and $x = 2$ as shown below:

$p (- 2) = (- 2)^{2} - 4 = 4 - 4 = 0 p (2) = 2^{2} - 4 = 4 - 4 = 0$

Hence the indicated numbers are the zeroes of the polynomial $p (x) = x^{2} - 4$ .

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Similar questions

Q. Verify whether the following are zeroes of the polynomial, indicated against them.
(i) p(x) = 3x + 1, x =

- \frac{1}{3}

(ii)

p (x) = 5 x - π, x = \frac{4}{5}

(iii)

p (x) = x^{2} - 1, x = 1, - 1

(iv) p(x) = (x +1) (x -2), x = - 1, 2

Q. Verify whether the following are zeroes of the polynomial, indicated against them.

p (x) = x^{2}, x = 0

Verify whether the following values indicated against them are zeroes of the polynomial.
$(i) p (x) = 5 x - π, x = \frac{4}{5}$
$(i i) p (x) = x^{2} - 1, x = 1, - 1$ [4 MARKS]

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Verify whether the indicated numbers are zero of the polynomial givenp(x)=x2−4 at x=2,x=−2

In the given polynomial p(x)=x2−4, substitute x=−2 and x=2 as shown below: p(−2)=(−2)2−4=4−4=0p(2)=22−4=4−4=0 Hence the indicated numbers are the zeroes of the polynomial p(x)=x2−4.

Verify whether the indicated numbers are zero of the polynomial given
$p (x) = x^{2} - 4$ at $x = 2, x = - 2$

In the given polynomial $p (x) = x^{2} - 4$ , substitute $x = - 2$ and $x = 2$ as shown below:

$p (- 2) = (- 2)^{2} - 4 = 4 - 4 = 0 p (2) = 2^{2} - 4 = 4 - 4 = 0$

Hence the indicated numbers are the zeroes of the polynomial $p (x) = x^{2} - 4$ .