Vernier calipers has 20 divisions. Its vernier scale which coincide with 19 divisions on the main scale. Least count of the instrument is 0.1 mm. The main scale division is:

0.5 mm

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1 mm

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2 mm

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0.25 mm

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Solution

The correct option is C 2 mm
$\begin{matrix} 20 V S D = 19 M S D 1 \times S D = \frac{19}{20} m s D . . . (i) L \cdot C = 0.1 m m \end{matrix}$

$\begin{matrix} L \cdot C = 1 M S D - 1 V S D 0.1 = lmsD - \frac{1 \times 19 M S D}{20} 0.1 = \frac{20 - 19 m s D}{20} 1 m s D = \frac{20 \times 0.1}{1} \end{matrix}$
$= 2 m m$

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Vernier calipers has 20 divisions. Its vernier scale which coincide with 19 divisions on the main scale. Least count of the instrument is 0.1 mm. The main scale division is:

The correct option is C 2 mm20VSD=19MSD1×SD=1920msD...(i)L⋅C=0.1 mmL⋅C=1MSD−1VSD0.1=lmsD−1×19MSD200.1=20−19msD201msD=20×0.11=2 mm