Vertex of the parabola $x^{2} + 12 x - 9 y = 0$ is

(6, - 4)

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(- 6, 4)

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(6, 4)

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(- 6, - 4)

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Solution

The correct option is C $(- 6, - 4)$
The equation can be re-written as,
$(x^{2} + 6)^{2} - 9 (y + 4) = 0$
$(x + 6)^{2} = 9 (y + 4)$
$(- 6, - 4)$ is the vertex.

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Vertex of the parabola x2+12x−9y=0 is

The correct option is C (−6,−4)The equation can be re-written as,(x2+6)2−9(y+4)=0(x+6)2=9(y+4)(−6,−4) is the vertex.

Vertex of the parabola $x^{2} + 12 x - 9 y = 0$ is

The correct option is C $(- 6, - 4)$
The equation can be re-written as,
$(x^{2} + 6)^{2} - 9 (y + 4) = 0$
$(x + 6)^{2} = 9 (y + 4)$
$(- 6, - 4)$ is the vertex.