Question

Vertex of the parabola $x^2+4x+2y-7=0$ is

• A.
• B.
• C.
• D.

Answer 1

The correct option is A

$(x+2{)}^2=-2y+7+4\Rightarrow (x+2{)}^2=-2(y-\frac{11}{2})$
Hence vertex is $(-2,\frac{11}{2})$.